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Results for Lysons, Chris Results for Lysons, Chris (Lancashire)

Results for Lysons, Chris (Lancashire)

ECF Grading Information

Current Standard Grading 98
Current Rapid Grading 106
Grading code 251140L (click link for full grading information)
Current (2017) ECF Member Number S13093 ECF   

From competitions in play from September 2009 onwards, opponents' gradings are fetched automatically from the ECF site. A missing grading implies that the player lists do not contain a valid Grade Code for that person, or that the present grade is blank. From 2011-12, grades are published in both July and January; both grades are listed.

Note: Cup results (if any) follow the oldest league results.

League results

No league results, except possibly in the test leagues, for this person since drop-down player lists were introduced (2006-07).

Cup results

 

2016-17 U100

Standard Gradings 99, 103
date for board against result
21 May 2017 Lancashire (H) 3 Mottram, Paul 96 Leicestershire 0
0 out of 1 (excluding defaults) = 0%

2015-16 U120

Standard Gradings 111, 105
date for board against result
14 May 2016 Lancashire (H) 7 Llewelyn, John 111 Warwickshire 0
0 out of 1 (excluding defaults) = 0%

2015-16 U140

Standard Gradings 111, 105
date for board against result
12Jun 2016 Lancashire (H) 14 Moss, David 121 Surrey 0
22 May 2016 Lancashire (H) 15 Bramley, Doug 109 Derbyshire 0.5
0.5 out of 2 (excluding defaults) = 25%

2014-15 Under 140

Standard Gradings 117, 118
date for board against result
09 May 2015 Lancashire (H) 12 Miles, Barry S 119 Surrey 1
13 June 2015 Lancashire (A) 12 Hillman, Graham 125 Kent 0
1 out of 2 (excluding defaults) = 50%

2013-14 Under 140

Standard Gradings 122, 123
date for board against result
18 May 2014 Lancashire (H) 10 Marshall, Alan R 129 Middlesex 1
14 JUN 2014 Lancashire (A) 10 Smith, Christopher 128 Hampshire 1
2 out of 2 (excluding defaults) = 100%

2012-13 Under 140

Standard Gradings 124, 125
date for board against result
19 May 2013 Lancashire (H) 15 Pickles, Alan 112 Shropshire 0
0 out of 1 (excluding defaults) = 0%