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Results for Griffiths, Jon Results for Griffiths, Jon (Leamington)

Results for Griffiths, Jon (Leamington)

ECF Rating Information

Current Standard Rating 1812 K
Current Rapid Rating
Rating code 111727A
Current (2023) ECF Member Number 8057 ECF   

From 2011-12 to 2019-20, grades were published in both July and January; both grades are listed. From 2020 onwards three-digit 'grades' were replaced by four-digit 'ratings'.

Opponents' ratings are fetched automatically from the ECF site. A missing rating implies that the a player's Rating Code has not been input by the team captain, or that the present rating is blank.

Note: Cup results (if any) follow the oldest league results.

League results

2021-2022 Leamington League Division 2

Standard rating 1833 initial, 1824 final
date for board against result
08 Dec 2021 Leamington A (A) 3 Summerfield, Julian H 1841 Solihull B 0.5
12 Jan 2022 Leamington A (A) 3 Johnson, Andy 1619 Daventry A 0.5
08 Feb 2022 Leamington A (H) 3 Summerfield, Julian H 1845 Solihull B 0.5
22 Feb 2022 Leamington A (A) 3 Gardiner, David 1901 Stratford A 0.5
08 Mar 2022 Leamington A (H) 3 Webb, Rod 1696 Kenilworth C 0.5
29 Mar 2022 Leamington A (H) 3 Christie, Gordon SG 1790 Shirley and Wythall B 0.5
3 out of 6 (excluding defaults) = 50%

2019-2020 Leamington League Division 2

Standard Gradings 149, 149
date for board against result
29 Jan 2020 Leamington A (A) 4 Johnson, Andy 126 Daventry A 1
1 out of 1 (excluding defaults) = 100%

2019-2020 Leamington League Division 3

Standard Gradings 149, 149
date for board against result
03 Feb 2020 Leamington B (A) 1 Ball, Roger 108 Shirley and Wythall D 1
11 Feb 2020 Leamington B (H) 2 Mycock, ken 127 Shirley and Wythall C 1
18 Feb 2020 Leamington B (H) 1 Zawadzki, Marek 128 Stratford B 0.5
2.5 out of 3 (excluding defaults) = 83.33%

Cup results

 

2021-2022 Leamington League U8750 Team KO

Standard rating 1833 initial, 1824 final
date for board against result
28 Sep 2021 Leamington (H) 1 Bowman, Kevin 1765 Daventry 0.5
0.5 out of 1 (excluding defaults) = 50%